Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: general nth term of series

  • To: mathgroup at smc.vnet.net
  • Subject: [mg62942] Re: [mg62921] general nth term of series
  • From: "Carl K. Woll" <carlw at wolfram.com>
  • Date: Fri, 9 Dec 2005 05:10:23 -0500 (EST)
  • References: <200512080827.DAA17935@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

n00dle0 at yahoo.com wrote:
> Hi,
> 
> Is there a way in mathematica to obtain the general term of a taylor
> series expansion?
> 
> \!\(G[u_, x_] = 1\/v\((1 - 2*x*u + u\^2)\)\)
> 
> Series[G[u, 0], {u, 0, 8}]
> 
> 
> Thanks,
> Ash


Ash,

Use SeriesTerm from the package RSolve:

Needs["DiscreteMath`RSolve`"]

In[15]:=
SeriesTerm[G[u,x],{u,0,n}]//OutputForm

Out[15]//OutputForm=
KroneckerDelta[-2 + n] - 2 x KroneckerDelta[-1 + n] + KroneckerDelta[n]
-----------------------------------------------------------------------
                                    v

Carl Woll
Wolfram Research


  • Prev by Date: Using The Random Function to predict Things
  • Next by Date: Re: How to hide a cell?
  • Previous by thread: general nth term of series
  • Next by thread: Re: general nth term of series