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Re: general nth term of series

  • To: mathgroup at
  • Subject: [mg62933] Re: general nth term of series
  • From: dh <dh at>
  • Date: Thu, 8 Dec 2005 06:25:37 -0500 (EST)
  • Organization: Cablecom Newsserver
  • References: <dn8qqq$hiq$>
  • Sender: owner-wri-mathgroup at

Hi Ash,
simply remember your math course:
n-th term = (1/n!) n-thederivative(f) (x-x0)^n

therefore, if f is an expression in x and we want the n-th term of the 
taylor series around x0 we may say:

TaylorTerm[f_, n_, x_, x0_] := (1/n!)(x - x0)^n (D[f, {x, n}] /. x -> x0)


n00dle0 at wrote:
> Hi,
> Is there a way in mathematica to obtain the general term of a taylor
> series expansion?
> \!\(G[u_, x_] = 1\/v\((1 - 2*x*u + u\^2)\)\)
> Series[G[u, 0], {u, 0, 8}]
> Thanks,
> Ash

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