Re: Simple task with Mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg63044] Re: Simple task with Mathematica
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Sun, 11 Dec 2005 22:25:18 -0500 (EST)
- Organization: The Open University, Milton Keynes, UK
- References: <dngvba$nd1$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Lea Rebanks wrote:
> Dear Sir / Madame,
>
> I am currently learning how to use Mathematica at college with a view to
> purchasing the program.
>
> Having spent a week studying the documentation / Book etc of version 4 I
> am struggling to do even the most simple tasks. I have looked at other
> Math programs, but I am really impressed with the numerical precision &
> scope of Mathematica. Below is an example of a really easy task which I
> can do in a second in Excel, however I am stuck with Mathematica 4.
> Please show me the correct code to do in Mathematica. Many thanks for
> your attention.
>
> Question:-
>
> Given the two columns below; I am trying to take the first column (A)
> created as a list & iterate it by starting with 5 to finish with the
> second column using the function A(1) = (6.5*2)-5 (starting value from
> the second column) = 8.
>
> Then, for A(2) = (9.5*2)-8 =11 etc, etc giving the second column.
> Function A(x) = x*2.
>
> (A)rea
>
> 5
>
>
> 6.5
>
> 8
>
>
> 9.5
>
> 11
>
>
> 8.5
>
> 6
>
>
> 4.5
>
> 3
>
>
> 9
>
> 15
>
>
> 12.5
>
> 10
>
>
> 12.5
>
> 15
>
>
> 17.5
>
> 20
>
>
> 18.5
>
> 17
>
>
> 11
>
> 5
>
>
>
> I have tried indexing with x = Range[11] & using A[[x]]-B[[x-1]]. Sorry,
> but I am really confused.
>
>
>
> Many thanks for any help you can offer.
>
>
>
> Best regards,
>
>
>
> Lea Rebanks.
>
Hi Lea,
Assuming I have understood correctly what you did with Excel, the
following lines are one of the possible approaches answering your question:
In[1]:=
A={6.5,9.5,8.5,4.5,9.0,12.5,12.5,17.5,18.5,11.0};
In[2]:=
B=FoldList[(#2*2-#1)&, 5., A]
Out[2]=
{5.,8.,11.,6.,3.,15.,10.,15.,20.,17.,5.}
Best regards,
/J.M.