Re: How to compute this sum?

• To: mathgroup at smc.vnet.net
• Subject: [mg63070] Re: [mg63041] How to compute this sum?
• From: Murray Eisenberg <murray at math.umass.edu>
• Date: Tue, 13 Dec 2005 03:40:52 -0500 (EST)
• Organization: Mathematics & Statistics, Univ. of Mass./Amherst
• References: <200512120325.WAA09948@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Your notation for the general term is confusing if not ambiguous: it has
the form a/b/c/d.  Do you really intend the form to be (a/b)/(c/d)?  If
so, then why don't you take a look at what happens to the nth term as n
tends to infinity, and then apply an appropriate theorem?

mizhael wrote:
> sum((-6*2^n*n+3*2^n+2*3^n*n)/(3^n)/(n^2-3*n+2)/(2^n),n = 1 .. Inf)
>
> thanks a lot!
>
>
>

--
Murray Eisenberg                     murray at math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower      phone 413 549-1020 (H)
University of Massachusetts                413 545-2859 (W)
710 North Pleasant Street            fax   413 545-1801
Amherst, MA 01003-9305

```

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