Re: 3d plot's of function's domain

*To*: mathgroup at smc.vnet.net*Subject*: [mg63146] Re: 3d plot's of function's domain*From*: dh <dh at metrohm.ch>*Date*: Thu, 15 Dec 2005 07:14:06 -0500 (EST)*References*: <dnrbr7$k7e$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi, try using Graphics`InequalityGraphics`InequalityPlot3D here is an example: f[x_, y_, z_] = 1 - (x^2 + y^2 + z^2); InequalityPlot3D[f[x, y, z] > 0, {x}, {y}, {z}] Daniel A D'Ignazio wrote: > Dear MathGroup, > > I would be very grateful if you could help me on this: > > I got a function of three variables f(x,y,z). I want to get a 3d plot of the > region A in R^3 such that for any vector of values (x,y,z) in A the function > f is positive. I'm only able to solve this problem in a basic way: I fix one > of the three variables -let's say z=Z -and then I get the 3d plot of the > function f(x,y| z=Z), get the contour plot and define the region of > interest. I can do it for several values of Z, but i think it is not very > elegant. > > There is a way to obtain directly the 3d plot of the variables space such > that the condition of f(.) being positive is satisfied? > > Many thanks > > A D > > _________________________________________________________________ > Scarica gratuitamente MSN Toolbar! http://toolbar.msn.it/ >