       Re: 3d plot's of function's domain

• To: mathgroup at smc.vnet.net
• Subject: [mg63146] Re: 3d plot's of function's domain
• From: dh <dh at metrohm.ch>
• Date: Thu, 15 Dec 2005 07:14:06 -0500 (EST)
• References: <dnrbr7\$k7e\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,
try using Graphics`InequalityGraphics`InequalityPlot3D
here is an example:

f[x_, y_, z_] = 1 - (x^2 + y^2 + z^2);
InequalityPlot3D[f[x, y, z] > 0, {x}, {y}, {z}]

Daniel

A D'Ignazio wrote:
> Dear MathGroup,
>
> I would be very grateful if you could help me on this:
>
> I got a function of three variables f(x,y,z). I want to get a 3d plot of the
> region A in R^3 such that for any vector of values (x,y,z) in A the function
> f is positive. I'm only able to solve this problem in a basic way: I fix one
> of the three variables -let's say z=Z -and then I get the 3d plot of the
> function f(x,y| z=Z), get the contour plot and define the region of
> interest. I can do it for several values of Z, but i think it is not very
> elegant.
>
> There is a way to obtain directly the 3d plot of the variables space such
> that the condition of f(.) being positive is satisfied?
>
> Many thanks
>
> A D
>
> _________________________________________________________________
> Scarica gratuitamente MSN Toolbar! http://toolbar.msn.it/
>

```

• Prev by Date: Re: Can I define 0^0 to be 1 for a notebook
• Next by Date: Re: Unexpected non-evaluation problem
• Previous by thread: Re: 3d plot's of function's domain
• Next by thread: Re: 3d plot's of function's domain