[Date Index]
[Thread Index]
[Author Index]
Re: Unexpected non-evaluation problem
*To*: mathgroup at smc.vnet.net
*Subject*: [mg63151] Re: Unexpected non-evaluation problem
*From*: dh <dh at metrohm.ch>
*Date*: Thu, 15 Dec 2005 07:14:11 -0500 (EST)
*References*: <dnrch3$kie$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hallo Carl,
go back to your analytic course notes and convince yourself that in a
strict sense the FourierTransform and its reverse of x^2 do not exist.
Only if the absolute value of a function is integrable will the
FourierTransfrom and its reverse exist.
Now Mathematica goes beyond this into the real of generalized functions,
that is distributions. There a FourierTransform does exist, but not its
reverse. I do not know enough about distributions to explain it
properly, but here is an heuristic explanation for the FourierTransfrom
of x^2:
The FourierTransform is defined as:
FT[x^2]¨= Integrate[ x^2 Exp[-I x y],{x,-Infinity,Infinity}]
x^2 is even, therefore instead of Exp[-I x y] we may use Cos[x y]:
FT[x^2]= Integrate[ x^2 Cos[ x y],{x,-Infinity,Infinity}]
Clearly this integral does not exist. However, we may calculate the
principal value where we take the limit:
Limit[ FT[x^2]= Integrate[ x^2 Cos[ x y],{x,-x0,x0}] ,{x0->Infinity}]
The indefinite integral gives:
(2*x*Cos[x*y])/y^2 + ((-2 + x^2*y^2)*Sin[x*y])/y^3
convince yourself that both terms are antisymetric in x, therefore, the
definite integral is zero for all y with the exception of y=0 where we
get infinity (something like 1/0^3)
have fun, Daniel
Carl Cotner wrote:
> I am totally baffled by the following Mathematica behavior:
>
> In[1]:= InverseFourierTransform[FourierTransform[x^2, x, y], y, x]
> Out[1]= Sqrt[2 Pi] x^2 FourierTransform[DiracDelta[y], y, x]
>
> In[2]:= Sqrt[2 Pi] x^2 FourierTransform[DiracDelta[y], y, x]
> Out[2]= x^2
>
> I've already asked my local guru without success, so I'm hoping someone
> here can help me. Does anyone know why the first expression doesn't
> evaluate to x^2 all by itself? How I can force it to do so?
>
> Carl
>
Prev by Date:
**Re: 3d plot's of function's domain**
Next by Date:
**Re: Re: Mathematica Programmer vs. Programming in Mathematica**
Previous by thread:
**Re: Unexpected non-evaluation problem**
Next by thread:
**Re: Unexpected non-evaluation problem**
| |