Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg63258] Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
  • From: "Steven T. Hatton" <hattons at globalsymmetry.com>
  • Date: Tue, 20 Dec 2005 23:35:42 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Is there a way to convince Mathematica to multiply Sqrt[a+b]Sqrt[a-b] to
produce Sqrt[a^2+b^2]?  
-- 
The Mathematica Wiki: http://www.mathematica-users.org/
Math for Comp Sci http://www.ifi.unizh.ch/math/bmwcs/master.html
Math for the WWW: http://www.w3.org/Math/


  • Prev by Date: problems with memory usage
  • Next by Date: "Alternating" function
  • Previous by thread: Re: problems with memory usage
  • Next by thread: Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]