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Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]

• To: mathgroup at smc.vnet.net
• Subject: [mg63258] Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
• From: "Steven T. Hatton" <hattons at globalsymmetry.com>
• Date: Tue, 20 Dec 2005 23:35:42 -0500 (EST)
• Sender: owner-wri-mathgroup at wolfram.com

Is there a way to convince Mathematica to multiply Sqrt[a+b]Sqrt[a-b] to
produce Sqrt[a^2+b^2]?  
-- 
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• Follow-Ups:
  • Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
    • From: Pratik Desai <pdesai1@umbc.edu>
  • Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
    • From: Andrzej Kozlowski <akoz@mimuw.edu.pl>
  • Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
    • From: Renan <renan.birck@gmail.com>