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Re: Convincing Mathematica that Sqrt[a+b]Sqrt[ab]==Sqrt[a^2+b^2]
 To: mathgroup at smc.vnet.net
 Subject: [mg63284] Re: Convincing Mathematica that Sqrt[a+b]Sqrt[ab]==Sqrt[a^2+b^2]
 From: Bhuvanesh <lalu_bhatt at yahoo.com>
 Date: Thu, 22 Dec 2005 00:04:49 0500 (EST)
 Sender: ownerwrimathgroup at wolfram.com
> Is there a way to convince Mathematica to multiply
> Sqrt[a+b]Sqrt[ab] to produce Sqrt[a^2+b^2]?
Simplify with assumptions can do it:
In[1]:= Simplify[Sqrt[a + b]*Sqrt[a  b], a >= b] //InputForm
Out[1]//InputForm= Sqrt[a^2  b^2]
Of course, that equality isn't true in general.
Bhuvanesh,
Wolfram Research.
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