Re: Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
- To: mathgroup at smc.vnet.net
- Subject: [mg63270] Re: [mg63258] Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt[a^2+b^2]
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Thu, 22 Dec 2005 00:04:32 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
expr=Sqrt[a+b]*Sqrt[a-b]; expr/.Sqrt[x_]*Sqrt[y_]:>Sqrt[x*y]//Simplify Sqrt[a^2 - b^2] Bob Hanlon > > From: "Steven T. Hatton" <hattons at globalsymmetry.com> To: mathgroup at smc.vnet.net > Date: 2005/12/20 Tue PM 11:35:42 EST > Subject: [mg63270] [mg63258] Convincing Mathematica that Sqrt[a+b]Sqrt[a-b]==Sqrt [a^2+b^2] > > Is there a way to convince Mathematica to multiply Sqrt[a+b]Sqrt[a-b] to > produce Sqrt[a^2+b^2]? > -- > The Mathematica Wiki: http://www.mathematica-users.org/ > Math for Comp Sci http://www.ifi.unizh.ch/math/bmwcs/master.html > Math for the WWW: http://www.w3.org/Math/ > >