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MathGroup Archive 2005

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Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)

  • To: mathgroup at
  • Subject: [mg53939] Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)
  • From: seidovzf at (Zak Seidov)
  • Date: Fri, 4 Feb 2005 04:12:23 -0500 (EST)
  • References: <q1pv8jc4sawh@legacy>
  • Sender: owner-wri-mathgroup at

or this should be 5/2?

On 3 Feb 05 14:56:06 -0500 (EST), Zak Seidov wrote:
>Dear Math gurus,
>I try to copy Math session:
>\!\(FullSimplify[\[Product]\+\(p = 2\)\%\[Infinity]\((\(p\^2 +
>1\)\/\(p\^2 - \1\))\)]
>n  Sinh[\[Pi]]\/\[Pi]\),
>that is,
> Product {for p=2 to infinity} (p^2+1)/(p^2-1)=>
>sinh(pi)/pi=3.67608 -
>is it OK,
>or this should be 3/2?
>Please email me your help:
>seidovzf at
>Many thanks,

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