Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)
- To: mathgroup at smc.vnet.net
- Subject: [mg53939] Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)
- From: seidovzf at yahoo.com (Zak Seidov)
- Date: Fri, 4 Feb 2005 04:12:23 -0500 (EST)
- References: <q1pv8jc4sawh@legacy>
- Sender: owner-wri-mathgroup at wolfram.com
or this should be 5/2? On 3 Feb 05 14:56:06 -0500 (EST), Zak Seidov wrote: >Dear Math gurus, >I try to copy Math session: >\!\(FullSimplify[\[Product]\+\(p = 2\)\%\[Infinity]\((\(p\^2 + >1\)\/\(p\^2 - \1\))\)] >n Sinh[\[Pi]]\/\[Pi]\), >that is, > Product {for p=2 to infinity} (p^2+1)/(p^2-1)=> >sinh(pi)/pi=3.67608 - >is it OK, >or this should be 3/2? >Please email me your help: >seidovzf at yahoo.com > >Many thanks, >Zak