Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)
- To: mathgroup at smc.vnet.net
- Subject: [mg53939] Re: Product {for p=2 to infinity} (p^2+1)/(p^2-1)
- From: seidovzf at yahoo.com (Zak Seidov)
- Date: Fri, 4 Feb 2005 04:12:23 -0500 (EST)
- References: <q1pv8jc4sawh@legacy>
- Sender: owner-wri-mathgroup at wolfram.com
or this should be 5/2?
On 3 Feb 05 14:56:06 -0500 (EST), Zak Seidov wrote:
>Dear Math gurus,
>I try to copy Math session:
>\!\(FullSimplify[\[Product]\+\(p = 2\)\%\[Infinity]\((\(p\^2 +
>1\)\/\(p\^2 - \1\))\)]
>n Sinh[\[Pi]]\/\[Pi]\),
>that is,
> Product {for p=2 to infinity} (p^2+1)/(p^2-1)=>
>sinh(pi)/pi=3.67608 -
>is it OK,
>or this should be 3/2?
>Please email me your help:
>seidovzf at yahoo.com
>
>Many thanks,
>Zak