Re: how to have a blind factorization of a polinomial?

*To*: mathgroup at smc.vnet.net*Subject*: [mg54123] Re: how to have a blind factorization of a polinomial?*From*: foice <NONfoiceSPAMMARE at tiscalinet.it>*Date*: Fri, 11 Feb 2005 03:33:36 -0500 (EST)*References*: <cud789$2t3$1@smc.vnet.net> <cuf453$gfb$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

On Thu, 10 Feb 2005 07:57:23 +0000 (UTC), "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de> wrote: >Sqrt[x + y] /. a_ + x :> x*(a/x + 1) Thanks for your help. Probably is a viable method, but is a little less than you expect for a WorldWideFamous software as Mathematica. In this way you can chose the form of the output, you can also do mistaques typing something like Sqrt[x^3 + y^2] /. a_ + x :> x^3*(a/x + 1) and mathematica will not prevent you from the error giving an output in the form Sqrt[x^3*(y^2/x+1)] Is mathematica so feature poor to allow only a "requested form" factorization? I can't belive it. Why there isn't somethig as Collect but that can use also negatieve powers to collect? i.e. Collect[x+y,x,Blind] giving x(1+y/x) Or better, at least for my task, a Mathematica command converting a function f(x,y) into a function f(x,y/x) (if possible) Thanks ------------------------------------------------------------- tutto ciò che ho scritto è sempre In My Humble Opinion (IMHO) probabilmente l'ho scritto di fretta, quindi scusate se sono stato sbrigativo.

**Follow-Ups**:**Re: Re: how to have a blind factorization of a polinomial?***From:*Daniel Lichtblau <danl@wolfram.com>

**Re: Re: how to have a blind factorization of a polinomial?***From:*Andrzej Kozlowski <akoz@mimuw.edu.pl>