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Re: Axes in ShowGraph
- To: mathgroup at smc.vnet.net
- Subject: [mg54269] Re: [mg54259] Axes in ShowGraph
- From: "David Park" <djmp at earthlink.net>
- Date: Mon, 14 Feb 2005 23:38:19 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Steve,
Yes, that is one of the features of ShowGraph. I don't know if there is a
way around it with the standard Combinatorica package.
However, the DrawGraph function in the CombinatoricaGraphics package at my
web site does draw the vertices at their actual location.
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
From: Steve Gray [mailto:stevebg at adelphia.net]
To: mathgroup at smc.vnet.net
I have a graph with 40 vertices, displayed with this function:
ShowGraph [ comgraph,
ImageSize -> 600,
Background -> RGBColor[.9, 1., .9],
VertexColor -> RGBColor[.5, .9, .9],
VertexStyle -> Disk[0.03],
VertexNumber -> True,
VertexNumberPosition -> Center,
TextStyle -> {FontSize -> 13, FontWeight -> Bold},
Axes -> True,
PlotRange -> All
];
Everything looks correct except the values displayed on the axes bear no
relation to the
values of the vertices given by Vertices[comgraph]. (PlotRange->Automatic
does the same thing.)
The vertices have the values shown below, while the displayed axes run from
about 0 to 0.64 on
X and .53 to 1.0 on Y. I need the actual vertex coordinates displayed as
they are given here:
In[50]:=
Vertices[comgraph]
Out[50]=
{{4.02,11.02},{3.71,5.73},{6.86,13.27},{-2.38,8.83},{1.69,11.97},{1.63,
14.08},{7.4,12.05},{7.54,11.46},{-3.85,13.21},{5.64,6.52},{2.66,
7.35},{-0.42,13.44},{-0.79,8.44},{-1.83,12.39},{3.831,7.7952},{3.7865,
7.0362},{4.2068,6.9192},{4.404,7.3913},{6.1905,11.6673},{6.4848,
12.372},{5.6225,12.6754},{4.1706,11.9777},{2.7813,11.3101},{1.0725,
10.489},{0.4406,10.1853},{-0.7015,9.6366},{-1.0597,9.4644},{-1.1438,
9.7837},{-0.6631,10.1546},{-0.1153,10.5772},{0.707,11.2116},{1.2879,
11.6598},{1.6789,12.3605},{-0.0049,12.6192},{-0.4754,12.6915},{-1.6347,
11.6483},{-0.6062,10.9233},{1.6612,9.3248},{0.3718,11.8744},{-0.5204,
12.0833}}
Users of the Graph functions are probably in the minority, but can anyone
explain this?
Steve Gray
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