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Re: Question about an integral


Version 5.1 (for Windows) gives the correct result with lots of conditions 
(I assume it's correct; I haven't checked all the conditions). However, you 
can coax out the result you want thus:

Assuming[A>2,Integrate[1/x^2,{x,2,A}]]

Steve Luttrell

"richard speers" <rspeers at skidmore.edu> wrote in message 
news:cv6ssi$6qb$1 at smc.vnet.net...
> The previous version of Mathematica integrated  1/x^2 from x=2 to x=A
> very nicely, giving 1/2-1/A.  The new
> version won't do the integral.  Please help.
> 



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