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MathGroup Archive 2005

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Re: Question about an integral

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54430] Re: Question about an integral
  • From: Bill Rowe <readnewsciv at earthlink.net>
  • Date: Sun, 20 Feb 2005 00:09:51 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

On 2/19/05 at 2:32 AM, rspeers at skidmore.edu (richard speers) wrote:

>The previous version of Mathematica integrated  1/x^2 from x=2 to
>x=A very nicely, giving 1/2-1/A.  The new version won't do the
>integral.

What version are you using?

In[1]:=
$Version
Integrate[1/x^2, {x, 2, A}, Assumptions -> Re[A] > 0]
Out[1]=
"5.1 for Mac OS X (October 25, 2004)"
Out[2]=
1/2 - 1/A

Or perhaps the issue is doing

In[7]:=
Integrate[1/x^2, {x, 2, A}]
Out[7]=
(A - 2)*If[Re[A] >= 0 || 
    Im[A] != 0, 1/(2*A), 
   Integrate[
    1/((A - 2)*x + 2)^2, 
    {x, 0, 1}, Assumptions -> 
      !(Re[A] >= 0 || 
       Im[A] != 0)]]


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