Re: Question about an integral
- To: mathgroup at smc.vnet.net
- Subject: [mg54430] Re: Question about an integral
- From: Bill Rowe <readnewsciv at earthlink.net>
- Date: Sun, 20 Feb 2005 00:09:51 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
On 2/19/05 at 2:32 AM, rspeers at skidmore.edu (richard speers) wrote:
>The previous version of Mathematica integrated 1/x^2 from x=2 to
>x=A very nicely, giving 1/2-1/A. The new version won't do the
>integral.
What version are you using?
In[1]:=
$Version
Integrate[1/x^2, {x, 2, A}, Assumptions -> Re[A] > 0]
Out[1]=
"5.1 for Mac OS X (October 25, 2004)"
Out[2]=
1/2 - 1/A
Or perhaps the issue is doing
In[7]:=
Integrate[1/x^2, {x, 2, A}]
Out[7]=
(A - 2)*If[Re[A] >= 0 ||
Im[A] != 0, 1/(2*A),
Integrate[
1/((A - 2)*x + 2)^2,
{x, 0, 1}, Assumptions ->
!(Re[A] >= 0 ||
Im[A] != 0)]]
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