Re: Re: Why does Inverse[M] hesitate?
- To: mathgroup at smc.vnet.net
- Subject: [mg54404] Re: [mg54383] Re: Why does Inverse[M] hesitate?
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Sun, 20 Feb 2005 00:08:04 -0500 (EST)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
Don't include the MatrixForm wrapper in the definition of the variables
(A={{(1-g)-1,1},{-w P(1-g)/C,-1}})//MatrixForm
(B={{0},{-P(w+1)}})//MatrixForm
Inverse[A].B
Bob Hanlon
>
> From: skirmantas.janusonis at yale.edu (Skirmantas)
To: mathgroup at smc.vnet.net
> Date: 2005/02/19 Sat AM 02:32:57 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg54404] [mg54383] Re: Why does Inverse[M] hesitate?
>
> The Inverse function sometimes calculates the inverse of a matrix
> immediately, sometimes it does not. Try this example in Mathematica
> 5.1:
>
> A={{(1-g)-1,1},{-w P(1-g)/C,-1}}//MatrixForm
> B={{0},{-P(w+1)}}//MatrixForm
>
> I get
> Out: Inverse[(expanded A)].(expanded B)
>
> If I do just
> A={{a,b},{c,d}}
> B={{e},{f}}
> Inverse[A].B
>
> I get the final correct result.
>
>