Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Re: Why does Inverse[M] hesitate?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54404] Re: [mg54383] Re: Why does Inverse[M] hesitate?
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sun, 20 Feb 2005 00:08:04 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

Don't include the MatrixForm wrapper in the definition of the variables

(A={{(1-g)-1,1},{-w P(1-g)/C,-1}})//MatrixForm
(B={{0},{-P(w+1)}})//MatrixForm

Inverse[A].B


Bob Hanlon

> 
> From: skirmantas.janusonis at yale.edu (Skirmantas)
To: mathgroup at smc.vnet.net
> Date: 2005/02/19 Sat AM 02:32:57 EST
> To: mathgroup at smc.vnet.net
> Subject: [mg54404] [mg54383] Re: Why does Inverse[M] hesitate?
> 
> The Inverse function sometimes calculates the inverse of a matrix
> immediately, sometimes it does not. Try this example in Mathematica
> 5.1:
> 
> A={{(1-g)-1,1},{-w P(1-g)/C,-1}}//MatrixForm
> B={{0},{-P(w+1)}}//MatrixForm
> 
> I get 
> Out: Inverse[(expanded A)].(expanded B)
> 
> If I do just 
> A={{a,b},{c,d}}
> B={{e},{f}}
> Inverse[A].B 
> 
> I get the final correct result. 
> 
> 


  • Prev by Date: Re: computing cumulative sum for list
  • Next by Date: Re: Re: Why does Inverse[M] hesitate?
  • Previous by thread: Re: Why does Inverse[M] hesitate?
  • Next by thread: Re: Why does Inverse[M] hesitate?