Re: Re: Why does Inverse[M] hesitate?
- To: mathgroup at smc.vnet.net
- Subject: [mg54387] Re: [mg54383] Re: Why does Inverse[M] hesitate?
- From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
- Date: Sun, 20 Feb 2005 00:07:47 -0500 (EST)
- References: <200502190732.CAA06180@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
On 19 Feb 2005, at 08:32, Skirmantas wrote: > The Inverse function sometimes calculates the inverse of a matrix > immediately, sometimes it does not. Try this example in Mathematica > 5.1: > > A={{(1-g)-1,1},{-w P(1-g)/C,-1}}//MatrixForm > B={{0},{-P(w+1)}}//MatrixForm > > I get > Out: Inverse[(expanded A)].(expanded B) > > If I do just > A={{a,b},{c,d}} > B={{e},{f}} > Inverse[A].B > > I get the final correct result. > The correct input is: (A = {{(1 - g) - 1, 1}, {-w P(1 - g)/C, -1}}) // MatrixForm (B = {{0}, {-P(w + 1)}}) // MatrixForm An expression with head MatrixForm is not a matrix. Andrzej Kozlowski Chiba, Japan http://www.akikoz.net/andrzej/index.html http://www.mimuw.edu.pl/~akoz/
- References:
- Re: Why does Inverse[M] hesitate?
- From: skirmantas.janusonis@yale.edu (Skirmantas)
- Re: Why does Inverse[M] hesitate?