Re: Solutions of an equation under complex form

*To*: mathgroup at smc.vnet.net*Subject*: [mg54501] Re: Solutions of an equation under complex form*From*: "Carl K. Woll" <carlw at u.washington.edu>*Date*: Tue, 22 Feb 2005 04:22:58 -0500 (EST)*Organization*: University of Washington*References*: <cvc7un$qqr$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Michaël, You can use RootReduce, e.g., Solve[x^2+x+1==0,x]//RootReduce Carl Woll "Michaël Monerau" <mmonerau at gmail.com> wrote in message news:cvc7un$qqr$1 at smc.vnet.net... > Hello, > > I'm running into a little problem under Mathematica 5.0 but I'm sure > people here will just take it as "too easy", but, well :) I just want > the solutions of the equation : > > x^2 + x + 1 == 0 > > under their complex form. > > So, I type : > > Solve [x^2 + x + 1 == 0, x] > > But I unfortunately get : > { { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } } > > And I'd prefer to obtain the more "readable" form : > -1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3] > > that I would get under another system for instance. What special function > should I call to get this form under Mathematica ? > > Thanks for any help > -- > Michaël Monerau > -= JJG =- >