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MathGroup Archive 2005

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Re: Solutions of an equation under complex form

  • To: mathgroup at smc.vnet.net
  • Subject: [mg54501] Re: Solutions of an equation under complex form
  • From: "Carl K. Woll" <carlw at u.washington.edu>
  • Date: Tue, 22 Feb 2005 04:22:58 -0500 (EST)
  • Organization: University of Washington
  • References: <cvc7un$qqr$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Michaël,

You can use RootReduce, e.g.,

Solve[x^2+x+1==0,x]//RootReduce

Carl Woll

"Michaël Monerau" <mmonerau at gmail.com> wrote in message 
news:cvc7un$qqr$1 at smc.vnet.net...
> Hello,
>
> I'm running into a little problem under Mathematica 5.0 but I'm sure
> people here will just take it as "too easy", but, well :) I just want
> the solutions of the equation :
>
> x^2 + x + 1 == 0
>
> under their complex form.
>
> So, I type :
>
> Solve [x^2 + x + 1 == 0, x]
>
> But I unfortunately get :
> { { {x -> -(-1)^(1/3) }, { x -> (-1)^(2/3) } } }
>
> And I'd prefer to obtain the more "readable" form :
> -1/2 + I*1/2*Sqrt[3], -1/2 - I*1/2*Sqrt[3]
>
> that I would get under another system for instance. What special function
> should I call to get this form under Mathematica ?
>
> Thanks for any help
> -- 
> Michaël Monerau
> -= JJG =-
> 



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