       Re: easy question about random numbers

• To: mathgroup at smc.vnet.net
• Subject: [mg53413] Re: easy question about random numbers
• From: Mark Fisher <mark at markfisher.net>
• Date: Tue, 11 Jan 2005 01:30:44 -0500 (EST)
• References: <crqb7f\$cak\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```With 5.1, we can use Piecewise as follows:

MakeDiscreteRandomFunction[probs_] :=
MakeDiscreteRandomFunction[probs, Range[Length[probs]]]

MakeDiscreteRandomFunction[probs_, vals_] :=
Block[{x},
Compile @@ {x, Piecewise @
Transpose[{vals, x <= # & /@ Rest@FoldList[Plus, 0, probs]}]}
]

li2= {1/6, 1/6, 1/6, 1/6, 9/60, 11/60}
ranfun = MakeDiscreteRandomFunction[li2]

Usage:

ranfun[Random[]]

--Mark

Pedrito wrote:

> Hi everybody!
>
> I wanted to obtain a discrete random number generator that I needed for
> a project.
>
> On the library Statistics`DiscreteDistributions` I could find the DiscreteUniformDistribution
> function. But I wanted to specify the probability for each one of the
> states.
>
>
> For instance:
> If we need to simulate an unfair dice, we could have this probabilities
> for each one of the sides:
> {1/6, 1/6, 1/6, 1/6, 9/60, 11/60}
>
> So I wrote:
> li2 = {1/6, 1/6, 1/6, 1/6, 9/60, 11/60}
> li3=FoldList[Plus,0,li2]
> Module[{i = 1, r = Random[]}, While[ !li3[[i]] < r < li3[[i + 1]], i++]; i]
>
> It works ok but I don't know if there is another (better) way of doing
> this.
> Any suggestion?
>

```

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