[Date Index]
[Thread Index]
[Author Index]
Re: Periodic function Roots
*To*: mathgroup at smc.vnet.net
*Subject*: [mg58401] Re: Periodic function Roots
*From*: dh <dh at metrohm.ch>
*Date*: Fri, 1 Jul 2005 02:01:54 -0400 (EDT)
*References*: <da0bka$fkj$1@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
do I understand your question right?
You want to get expansion coefficients A,B,.. in a cosine expansion of
the periodic function K.
Toward this aim, there is:
Calculus`FourierTransform`FourierCosCoefficient
here is an example: Let K= Mod[t^2,2 Pi] then we get the n-th expansion
coefficient by:
FourierCosCoefficient[Mod[t^2, 2Pi], t, n]
the first few are: {1/12, -Pi^(-2), 1/(4*Pi^2),
-1/(9*Pi^2)}
sincerely, Daniel
FBellas wrote:
> Hello, I'm trying to solve an periodic ecuation involving several harmonics
> (Style ACos(x)+BCos(2x)+...==K). Mathematica can't let me us 'Solve'
> function, so it gives me the error:
> Solve::tdep: The equations appear to involve the variables to be solved for
> \
> in an essentially non-algebraic way.
>
> To arrange this, i'm making a little program involving FindRoot function to
> find at least two roots from the ecuation in the first period. But I would
> like to know if there are some other method to do this more easily.
>
> Thanks a lot
>
> F. Bellas
>
>
>
>
>
>
Prev by Date:
**a question about the UnitStep function**
Next by Date:
**Explicit solution to Root[]**
Previous by thread:
** Re: a question about the UnitStep function**
Next by thread:
**Re: Periodic function Roots**
| |