Re: evaluate assuming odd integers?

*To*: mathgroup at smc.vnet.net*Subject*: [mg59006] Re: evaluate assuming odd integers?*From*: "Steve Luttrell" <steve_usenet at _removemefirst_luttrell.org.uk>*Date*: Tue, 26 Jul 2005 04:03:22 -0400 (EDT)*References*: <dc1t2f$4v8$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Simplify[Integrate[Sin[(2m+1)*Pi*(z/L)], {z, 0, L}],Assumptions->m\[Element]Integers] (2*L)/(Pi + 2*m*Pi) Steve Luttrell "ab at sd.com" <at2 at ads.com> wrote in message news:dc1t2f$4v8$1 at smc.vnet.net... > Is there a way in Mathematica to evaluate an expression assuming some > varialbe is Odd integer, for example in below integral how can i tell it > that n is odd integer in the Assumptions section of FullSimplify command > or > the integral itself??: > In[35]:= > Integrate[Sin[n*Pi*(z/L)], {z, 0, L}] > FullSimplify[%, n \[Element] Integers && n >= 0 && > L \[Element] Reals && L > 0 && z \[Element] Reals] >