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Re: evaluate assuming odd integers?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg58976] Re: [mg58961] evaluate assuming odd integers?
*From*: Andrzej Kozlowski <akoz at mimuw.edu.pl>
*Date*: Tue, 26 Jul 2005 04:01:41 -0400 (EDT)
*References*: <200507250512.BAA04841@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
On 25 Jul 2005, at 07:12, ab at sd.com wrote:
> Is there a way in Mathematica to evaluate an expression assuming some
> varialbe is Odd integer, for example in below integral how can i
> tell it
> that n is odd integer in the Assumptions section of FullSimplify
> command or
> the integral itself??:
> In[35]:=
> Integrate[Sin[n*Pi*(z/L)], {z, 0, L}]
> FullSimplify[%, n \[Element] Integers && n >= 0 &&
> L \[Element] Reals && L > 0 && z \[Element] Reals]
>
>
All you *actually* need is:
Simplify[Integrate[Sin[(Pi*n*z)/L], {z, 0, L}],
Mod[n, 2] == 1]
(2*L)/(n*Pi)
Andrzej Kozlowski
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