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MathGroup Archive 2005

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Re: evaluate assuming odd integers?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg58976] Re: [mg58961] evaluate assuming odd integers?
  • From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
  • Date: Tue, 26 Jul 2005 04:01:41 -0400 (EDT)
  • References: <200507250512.BAA04841@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

On 25 Jul 2005, at 07:12, ab at sd.com wrote:

> Is there a way in Mathematica to evaluate an expression assuming some
> varialbe is Odd integer, for example in below integral how can i  
> tell it
> that n is odd integer in the Assumptions section of FullSimplify  
> command or
> the integral itself??:
> In[35]:=
> Integrate[Sin[n*Pi*(z/L)], {z, 0, L}]
> FullSimplify[%, n \[Element] Integers && n >= 0 &&
> L \[Element] Reals && L > 0 && z \[Element] Reals]
>
>


All you *actually* need is:



Simplify[Integrate[Sin[(Pi*n*z)/L], {z, 0, L}],
   Mod[n, 2] == 1]


(2*L)/(n*Pi)

Andrzej Kozlowski


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