Re: Simplification question
- To: mathgroup at smc.vnet.net
- Subject: [mg59067] Re: [mg59032] Simplification question
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Thu, 28 Jul 2005 02:26:14 -0400 (EDT)
- Reply-to: hanlonr at cox.net
- Sender: owner-wri-mathgroup at wolfram.com
The rules that it applies don't come up with a simpler form LeafCount[Cos[3*m*Pi]] 5 Simplify[Cos[3*m*Pi]//TrigToExp,Assumptions->Element[m,Integers]] (-1)^(-3*m) LeafCount[%] 5 Simplify[#,Assumptions->Element[m,Integers]]&/@(Cos[3*m*Pi]// TrigExpand) (-1)^(3*m) LeafCount[%] 5 Bob Hanlon > > From: "snoofly" <snoofly at snoofly.com> To: mathgroup at smc.vnet.net > Date: 2005/07/27 Wed AM 01:25:00 EDT > Subject: [mg59067] [mg59032] Simplification question > > Can someone explain this to me please. > > Clear[m] > > Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers] > 0 > > Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers] > > Cos[3 m \[Pi]] > > I'm not sure why Mathematica cannot deduce that the second simplification > should be (1)^m. > >