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Re: Simplification question

• To: mathgroup at smc.vnet.net
• Subject: [mg59067] Re: [mg59032] Simplification question
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Thu, 28 Jul 2005 02:26:14 -0400 (EDT)
• Reply-to: hanlonr at cox.net
• Sender: owner-wri-mathgroup at wolfram.com

The rules that it applies don't come up with a simpler form

LeafCount[Cos[3*m*Pi]]

5

Simplify[Cos[3*m*Pi]//TrigToExp,Assumptions->Element[m,Integers]]

(-1)^(-3*m)

LeafCount[%]

5

Simplify[#,Assumptions->Element[m,Integers]]&/@(Cos[3*m*Pi]//
TrigExpand)

(-1)^(3*m)

LeafCount[%]

5


Bob Hanlon

> 
> From: "snoofly" <snoofly at snoofly.com>
To: mathgroup at smc.vnet.net
> Date: 2005/07/27 Wed AM 01:25:00 EDT
> Subject: [mg59067] [mg59032] Simplification question
> 
> Can someone explain this to me please.
> 
> Clear[m]
> 
> Simplify[Sin[3 m Pi], Assumptions -> m \[Element] Integers]
> 0
> 
> Simplify[Cos[3 m Pi], Assumptions -> m \[Element] Integers]
> 
> Cos[3 m \[Pi]]
> 
> I'm not sure why Mathematica cannot deduce that the second simplification 
> should be (1)^m.
> 
>