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MathGroup Archive 2005

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Re: How to simplify an expression in version 5

  • To: mathgroup at smc.vnet.net
  • Subject: [mg59087] Re: [mg59022] How to simplify an expression in version 5
  • From: yehuda ben-shimol <bsyehuda at gmail.com>
  • Date: Thu, 28 Jul 2005 02:27:39 -0400 (EDT)
  • References: <200507270524.BAA19903@smc.vnet.net>
  • Reply-to: yehuda ben-shimol <bsyehuda at gmail.com>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,
Try to use Expand
<< Calculus`FourierTransform`
FourierTrigSeries[Cos[t], t, 5, FourierParameters -> {0, 1/Pi}]//Expand
will do the trick
yehuda

On 7/27/05, passwd9 <david at carter-hitchin.clara.co.uk> wrote:
> Hi,
> 
> I'm trying to simplify the expression that comes out of the
> FourierTrigSeries function, and I've tried 'Simplify', 'Collect' and
> 'Factor' but no luck.  My input is as follows:
> 
> << Calculus`FourierTransform`
> FourierTrigSeries[Cos[t], t, 5, FourierParameters -> {0, 1/Pi}]
> 
> And the output is:
> 
> \!\(\(2\/\@\[Pi] + \(4\ Cos[2\ t]\)\/\(3\ \@\[Pi]\) - \(4\ Cos[4\
> t]\)\/\(15\ \
> \@\[Pi]\) + \(4\ Cos[6\ t]\)\/\(35\ \@\[Pi]\) - \(4\ Cos[8\ t]\)\/\(63\
> \@\
> \[Pi]\) + \(4\ Cos[10\ t]\)\/\(99\ \@\[Pi]\)\)\/\@\[Pi]\)
> 
> That's rather horrid looking in ascii, so I'll try to make something
> more readable:
> 
> (2/Sqrt(Pi) + 4Cos(2t)/3Sqrt(Pi) - 4Cos(4t)/15Sqrt(Pi) + ... )
> ---------------------------------------------------------------
>                             Sqrt(Pi)
> 
> 
> Now the Sqrt(Pi) in the denominator could be 'brought up' into the
> terms in the numerator to give:
> 
> 
> (2/Pi + 4Cos(2t)/3Pi - 4Cos(4t)/15Pi + ... )
> 
> Much more elegant!  Anyone know if MM can do this?
> 
> Thanks.
> 
>


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