Re: Simplify expression

• To: mathgroup at smc.vnet.net
• Subject: [mg57804] Re: Simplify expression
• From: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>
• Date: Thu, 9 Jun 2005 05:17:36 -0400 (EDT)
• Organization: Uni Leipzig
• References: <d8697g\$c9t\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,

you can't because Sqrt[[(x1^2-x2^2)^2] is
Abs[x1^2-x2^2]

Regards
Jens

"Mukhtar Bekkali" <mbekkali at gmail.com> schrieb im
Newsbeitrag news:d8697g\$c9t\$1 at smc.vnet.net...
>I need to solve system of equations
>f1[x1,x2]=0,f2[x1,x2]==0, however,
> some elements of these equation have the form
> Sqrt[(x1^2-x2^2)^2].  It
> takes really long time to solve.  If, however, I
> manually simplify
> those elements, for example,
> Sqrt[(x1^2-x2^2)^2]=x1^2-x2^2 then solve
> is fast.  Therefore, the question is how I can
> force mathematica
> simplify expressions of this sort (another
> elements are fractions that
> depend on x1 and x2 in Mathematica's mind but in
> reality they cancel
> out and fraction becomes a number). I do not
> want to use FindRoot since
> I want to see all solutions. Thanks, Mukhtar
> Bekkali
>

```

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