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Re: Common factors in a list


Hi,

ClearAttributes[Times, Listable]

{a x, a y, a z} /. {a*b_, c___} :> a*{b, Sequence 
@@ (#/a & /@ {c})}

Regards

  Jens

"John Reed" <nospamjreed at alum.mit.edu> schrieb im 
Newsbeitrag news:d9r50q$568$1 at smc.vnet.net...
> I'm working with a list (vector) that's composed 
> of functions such as
> complex exponentials and Bessel functions.  Some 
> of the functions are common
> to each element of the list.  I'm trying to find 
> a way to do the following:
>
>   {a x, a y, a z}-> a *{x, y, z}
>
> In this expression, a, x, y, z are polynomials, 
> exponentials and/or Bessel
> functions.
>
> So far I haven't had any luck with this.  Does 
> anyone have a simple
> solution?
>
> John Reed
> 



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