Re: Common factors in a list

*To*: mathgroup at smc.vnet.net*Subject*: [mg58358] Re: Common factors in a list*From*: "Jens-Peer Kuska" <kuska at informatik.uni-leipzig.de>*Date*: Tue, 28 Jun 2005 21:56:53 -0400 (EDT)*Organization*: Uni Leipzig*References*: <d9r50q$568$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hi, ClearAttributes[Times, Listable] {a x, a y, a z} /. {a*b_, c___} :> a*{b, Sequence @@ (#/a & /@ {c})} Regards Jens "John Reed" <nospamjreed at alum.mit.edu> schrieb im Newsbeitrag news:d9r50q$568$1 at smc.vnet.net... > I'm working with a list (vector) that's composed > of functions such as > complex exponentials and Bessel functions. Some > of the functions are common > to each element of the list. I'm trying to find > a way to do the following: > > {a x, a y, a z}-> a *{x, y, z} > > In this expression, a, x, y, z are polynomials, > exponentials and/or Bessel > functions. > > So far I haven't had any luck with this. Does > anyone have a simple > solution? > > John Reed >