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MathGroup Archive 2005

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Re: Common factors in a list

  • To: mathgroup at
  • Subject: [mg58349] Re: Common factors in a list
  • From: dh <dh at>
  • Date: Tue, 28 Jun 2005 21:56:46 -0400 (EDT)
  • References: <d9r50q$568$>
  • Sender: owner-wri-mathgroup at

Hi John,
you could try to create a polynomial in a new variable, say z, from your 
vector by:
v={a x, a y, a z};
pol=Table[z^i,{i,Length[v]}] . v
now you could extract a common factor by:
com= FactorTerms[pol,z][[1]]
the residual vector you get from:

sincerely, Daniel

John Reed wrote:
> I'm working with a list (vector) that's composed of functions such as 
> complex exponentials and Bessel functions.  Some of the functions are common 
> to each element of the list.  I'm trying to find a way to do the following:
>    {a x, a y, a z}-> a *{x, y, z}
> In this expression, a, x, y, z are polynomials, exponentials and/or Bessel 
> functions.
> So far I haven't had any luck with this.  Does anyone have a simple 
> solution?
> John Reed 

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