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Re: Re: Simplfying inside Sqrt
*To*: mathgroup at smc.vnet.net
*Subject*: [mg55138] Re: [mg55122] Re: Simplfying inside Sqrt
*From*: DrBob <drbob at bigfoot.com>
*Date*: Mon, 14 Mar 2005 03:43:37 -0500 (EST)
*References*: <d0u7bj$kph$1@smc.vnet.net> <200503130957.EAA09949@smc.vnet.net>
*Reply-to*: drbob at bigfoot.com
*Sender*: owner-wri-mathgroup at wolfram.com
PowerExpand[Factor /@ Sqrt[x^2 + x^4]]
x*Sqrt[1 + x^2]
Bobby
On Sun, 13 Mar 2005 04:57:40 -0500 (EST), Peter Pein <petsie at arcor.de> wrote:
> billkavanagh at gmail.com wrote:
>
>> Hi
>>
>> I'm wondering how to tell mathematica that I want terms like
>> Sqrt[x^2+x^4] to be x*Sqrt[1+x^2]. I have an expression with a few
>> terms like this in it so manually inserting a
>> PowerExpand[Sqrt[Expand[x^2+x^4]] is no good to me.
>>
>> I've tried a general PowerExpand and Simplify with a Im[x]==0 around
>> the whole expression but with no luck.
>>
>> Does anybody know how to do this?
>>
>> Thanks,
>> Bill
>>
>> --
>> William R. Kavanagh
>> http://www.physics.mun.ca/~wkavanag
>>
> There /has/ to be something more simple than
>
> Simplify[#1, x >= 0] & /@
> (Sqrt[x^2 + x^4] /. (a_)^(b_) :> (#1^b & ) /@ Factor[a])
>
> but I don't see it at the moment.
>
--
DrBob at bigfoot.com
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