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Re: Re: Simplifying ArcTan


But why this restriction? I thought the whole point of the two argument
ArcTan was that it covered the entire circle, taking signs into account. The
two argument ArcTan is a great idea that is incorporated into Mathematica.
It would be even greater if Simplify knew the identity...

ArcTan[Cos[x],Sin[x]] == x

Is there any reason that should not be true?

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/


From: Bob Hanlon [mailto:hanlonr at cox.net]
To: mathgroup at smc.vnet.net


Simplify[ArcTan[Cos[x],Sin[x]],0<=x<Pi/2]

x


Bob Hanlon




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