Re: Re: Simplifying ArcTan

*To*: mathgroup at smc.vnet.net*Subject*: [mg55567] Re: [mg55542] Re: [mg55526] Simplifying ArcTan*From*: "David Park" <djmp at earthlink.net>*Date*: Wed, 30 Mar 2005 03:21:00 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

But why this restriction? I thought the whole point of the two argument ArcTan was that it covered the entire circle, taking signs into account. The two argument ArcTan is a great idea that is incorporated into Mathematica. It would be even greater if Simplify knew the identity... ArcTan[Cos[x],Sin[x]] == x Is there any reason that should not be true? David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: Bob Hanlon [mailto:hanlonr at cox.net] To: mathgroup at smc.vnet.net Simplify[ArcTan[Cos[x],Sin[x]],0<=x<Pi/2] x Bob Hanlon

**Follow-Ups**:**Re: Re: Re: Simplifying ArcTan***From:*DrBob <drbob@bigfoot.com>