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Re: Re: Re: Simplifying ArcTan


> ArcTan[Cos[x],Sin[x]] == x

The RHS function is one-to-one, but the LHS is periodic in x. They only agree on an interval.

Bobby

On Wed, 30 Mar 2005 03:21:00 -0500 (EST), David Park <djmp at earthlink.net> wrote:

> But why this restriction? I thought the whole point of the two argument
> ArcTan was that it covered the entire circle, taking signs into account. The
> two argument ArcTan is a great idea that is incorporated into Mathematica.
> It would be even greater if Simplify knew the identity...
>
> ArcTan[Cos[x],Sin[x]] == x
>
> Is there any reason that should not be true?
>
> David Park
> djmp at earthlink.net
> http://home.earthlink.net/~djmp/
>
>
> From: Bob Hanlon [mailto:hanlonr at cox.net]
To: mathgroup at smc.vnet.net
> To: mathgroup at smc.vnet.net
>
>
> Simplify[ArcTan[Cos[x],Sin[x]],0<=x<Pi/2]
>
> x
>
>
> Bob Hanlon
>
>
>
>
>
>



-- 
DrBob at bigfoot.com


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