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Re: Summation problem


Hi!

> Sum[I^n/n,{n,1,Infinity}]
    On Math4 it gives:
             -Log[1 - I]

> Sum[I^(n+1)/n,{n,1,Infinity}]
>
On Math4 it gives:
            -I Log[1 - I]

> Jaroslaw Piskorski

Regards,
    ~Scout~ 


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