Re: Summation problem
- To: mathgroup at smc.vnet.net
- Subject: [mg56636] Re: Summation problem
- From: "Dr. Wolfgang Hintze" <weh at snafu.de>
- Date: Sun, 1 May 2005 00:46:33 -0400 (EDT)
- References: <d4v6br$nq9$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
(Knowing that statetments like this don't really help)
I cannot spot the problem
In[1]:=
Sum[I^n/n, {n, 1, Infinity}]
Out[1]=
-Log[1 - I]
In[2]:=
Sum[I^(n + 1)/n, {n, 1, Infinity}]
Out[2]=
-I*Log[1 - I]
In[3]:=
$Version
Out[3]=
"4.0 for Microsoft Windows (April 21, 1999)"
Regards,
Wolfgang
jaropis wrote:
> Why can't Mathematica sum:
> Sum[I^n/n,{n,1,Infinity}]
> and gives the (incorrect) answer, that this is divergent while it can do:
> Sum[I^(n+1)/n,{n,1,Infinity}]
> correctly?
>
> Jaroslaw Piskorski
>
>