Re: is this solvable?

*To*: mathgroup at smc.vnet.net*Subject*: [mg56630] Re: is this solvable?*From*: "dennis" <dwangsness at earthlink.net>*Date*: Sun, 1 May 2005 00:46:26 -0400 (EDT)*References*: <d4sov7$ale$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

The only function I know with its derivative proportional to itself is the exponential. Therefore, I think the solution is trivial if p1 and p2 are constants. a[t] = a0*Exp[-p1*t] and b[t] = b0*Exp[-p2*t] I know this isn't using Mathematica to get the solution, but the problem seems trivial if what you want is the solution and not a method in Mathematica. Regards, Dennis ames_kin at yahoo.com wrote: > a'[t] + b'[t]== -p1 a[t] - p2 b[t] > > where {a[0]== a0, b[0]== b0} > > is this solvable in Mathematica? If so, how will I go about doing so? > > let's assume a[0]== a0, and b[0]==b0 > > if symbolic solution isn't possible, then intial conditions of > a[0]== 1, and b[0]==0.5 couild be used...(or any other numbers for that > matter) > > thanks in advance.