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Re: Summation problem


jaropis wrote:

> Why can't Mathematica sum:
> Sum[I^n/n,{n,1,Infinity}]
> and gives the (incorrect) answer, that this is divergent while it
> can do: Sum[I^(n+1)/n,{n,1,Infinity}]
> correctly?

seems to be a new feature in 5.1 ...


In[1]:= Sum[I^n/n, {n, 1, Infinity}]
 
Sum::div: Sum does not converge.
 
Sum::div: Sum does not converge.
 
             n
            I
Out[1]= Sum[--, {n, 1, Infinity}]
            n
 
In[2]:= Sum[I^(n + 1)/n, {n, 1, Infinity}]
 
Out[2]= -I Log[1 - I]
 
In[3]:= $Version
 
Out[3]= 5.1 for Linux (October 25, 2004)


Regards,
Marcus

-- 
What is life but a series of inspired follies? -- George Bernard Shaw


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