Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: calculate de Jong function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg56990] Re: calculate de Jong function
  • From: dh <dh at metrohm.ch>
  • Date: Thu, 12 May 2005 02:32:25 -0400 (EDT)
  • References: <d5skfb$nv0$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi Stefan,
there is the Length function that gives you the length of e.g. a vector, 
that is the dimension of your x.
In version 5.1 there is the function Norm that can make your life still 
easier.
Sincerely, Daniel

Stefan Schuster wrote:
> Hello,
> 
> I don't know how I should implement the first de jong function:
> 
> f(x)=Sum((x_i)^2)
> where x is a Vector with n dimensions and x_i is the value of the i-th 
> Dimension.
> i.e. all Values of the Vector are squared and added.
> 
> My problem is that I don't know how many Dimensions there are, so I 
> can't define the borders of the SUM function.
> 
> thanks in advance for help
> 
> Stefan
> 


  • Prev by Date: Re: Remote Kernel
  • Next by Date: Re: solve() problem since new ROM update
  • Previous by thread: Re: calculate de Jong function
  • Next by thread: Re: calculate de Jong function