Re: Integration under Mathematica 5.0

*To*: mathgroup at smc.vnet.net*Subject*: [mg57459] Re: [mg57417] Integration under Mathematica 5.0*From*: Chris Chiasson <chris.chiasson at gmail.com>*Date*: Sat, 28 May 2005 05:39:53 -0400 (EDT)*References*: <200505270856.EAA07672@smc.vnet.net>*Reply-to*: Chris Chiasson <chris.chiasson at gmail.com>*Sender*: owner-wri-mathgroup at wolfram.com

Mine gives the aforementioned answer. Of course, I have the same version as mentioned above. On 5/27/05, José Carlos Santos <jcsantos at fc.up.pt> wrote: > Hi all, > > At another newsgroup, someone has transcribed this Mathematica > session: > > In[1]:=$Version > > Out[1]=5.0 for Microsoft Windows (November 18, 2003) > > In[2]:=Integrate[Sqrt[1+Sqrt[u]]/(E^(a*u)*(2*Sqrt[2]*Sqrt[u])),{u,0,1}] > > Out[2]=(1/3)*(4 - Sqrt[2]) > > This makes no sense, because the integral does depend upon the parameter > _a_ (just ask Mathematica to plot the graph). I do not have access to > Mathematica 5.0, but under the version 4.0 I do not get that answer; > what I get is the same integral written in a slightly different form. > > Can someone reproduce that behaviour? And, if it is possible to > reproduce it, can someone *explain* it? > > BTW, the value (1/3)*(4 - Sqrt[2]) is the value of the integral when > a = 0. > > Best regards, > > Jose Carlos Santos > > -- Chris Chiasson http://chrischiasson.com/ 1 (810) 265-3161

**References**:**Integration under Mathematica 5.0***From:*José Carlos Santos <jcsantos@fc.up.pt>