Re: Integration under Mathematica 5.0
- To: mathgroup at smc.vnet.net
- Subject: [mg57459] Re: [mg57417] Integration under Mathematica 5.0
- From: Chris Chiasson <chris.chiasson at gmail.com>
- Date: Sat, 28 May 2005 05:39:53 -0400 (EDT)
- References: <200505270856.EAA07672@smc.vnet.net>
- Reply-to: Chris Chiasson <chris.chiasson at gmail.com>
- Sender: owner-wri-mathgroup at wolfram.com
Mine gives the aforementioned answer. Of course, I have the same
version as mentioned above.
On 5/27/05, José Carlos Santos <jcsantos at fc.up.pt> wrote:
> Hi all,
>
> At another newsgroup, someone has transcribed this Mathematica
> session:
>
> In[1]:=$Version
>
> Out[1]=5.0 for Microsoft Windows (November 18, 2003)
>
> In[2]:=Integrate[Sqrt[1+Sqrt[u]]/(E^(a*u)*(2*Sqrt[2]*Sqrt[u])),{u,0,1}]
>
> Out[2]=(1/3)*(4 - Sqrt[2])
>
> This makes no sense, because the integral does depend upon the parameter
> _a_ (just ask Mathematica to plot the graph). I do not have access to
> Mathematica 5.0, but under the version 4.0 I do not get that answer;
> what I get is the same integral written in a slightly different form.
>
> Can someone reproduce that behaviour? And, if it is possible to
> reproduce it, can someone *explain* it?
>
> BTW, the value (1/3)*(4 - Sqrt[2]) is the value of the integral when
> a = 0.
>
> Best regards,
>
> Jose Carlos Santos
>
>
--
Chris Chiasson
http://chrischiasson.com/
1 (810) 265-3161
- References:
- Integration under Mathematica 5.0
- From: José Carlos Santos <jcsantos@fc.up.pt>
- Integration under Mathematica 5.0