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MathGroup Archive 2005

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Re: Integration under Mathematica 5.0

  • To: mathgroup at smc.vnet.net
  • Subject: [mg57459] Re: [mg57417] Integration under Mathematica 5.0
  • From: Chris Chiasson <chris.chiasson at gmail.com>
  • Date: Sat, 28 May 2005 05:39:53 -0400 (EDT)
  • References: <200505270856.EAA07672@smc.vnet.net>
  • Reply-to: Chris Chiasson <chris.chiasson at gmail.com>
  • Sender: owner-wri-mathgroup at wolfram.com

Mine gives the aforementioned answer. Of course, I have the same
version as mentioned above.

On 5/27/05, José Carlos Santos <jcsantos at fc.up.pt> wrote:
> Hi all,
> 
> At another newsgroup, someone has transcribed this Mathematica
> session:
> 
> In[1]:=$Version
> 
> Out[1]=5.0 for Microsoft Windows (November 18, 2003)
> 
> In[2]:=Integrate[Sqrt[1+Sqrt[u]]/(E^(a*u)*(2*Sqrt[2]*Sqrt[u])),{u,0,1}]
> 
> Out[2]=(1/3)*(4 - Sqrt[2])
> 
> This makes no sense, because the integral does depend upon the parameter
> _a_ (just ask Mathematica to plot the graph). I do not have access to
> Mathematica 5.0, but under the version 4.0 I do not get that answer;
> what I get is the same integral written in a slightly different form.
> 
> Can someone reproduce that behaviour? And, if it is possible to
> reproduce it, can someone *explain* it?
> 
> BTW, the value (1/3)*(4 - Sqrt[2]) is the value of the integral when
> a = 0.
> 
> Best regards,
> 
> Jose Carlos Santos
> 
> 


-- 
Chris Chiasson
http://chrischiasson.com/
1 (810) 265-3161


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