       Re: Integration under Mathematica 5.0

• To: mathgroup at smc.vnet.net
• Subject: [mg57434] Re: [mg57417] Integration under Mathematica 5.0
• From: "Owen, HL \(Hywel\)" <h.l.owen at dl.ac.uk>
• Date: Sat, 28 May 2005 05:38:57 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

```Yes, I get this behaviour in 5.1

Integrate[Sqrt[1 + Sqrt[u]]/(
E^(a*u)*(2*Sqrt*Sqrt[u])), {u, 0, 1}, Assumptions -> a > 0]

gives

(1/3)*(4 - Sqrt)

> -----Original Message-----
> From: José Carlos Santos [mailto:jcsantos at fc.up.pt]
To: mathgroup at smc.vnet.net
> Sent: 27 May 2005 09:57
> Subject: [mg57434] [mg57417] Integration under Mathematica 5.0
>
>
> Hi all,
>
> At another newsgroup, someone has transcribed this Mathematica
> session:
>
> In:=\$Version
>
> Out=5.0 for Microsoft Windows (November 18, 2003)
>
> In:=Integrate[Sqrt[1+Sqrt[u]]/(E^(a*u)*(2*Sqrt*Sqrt[u]))
> ,{u,0,1}]
>
> Out=(1/3)*(4 - Sqrt)
>
> This makes no sense, because the integral does depend upon
> the parameter
> Mathematica 5.0, but under the version 4.0 I do not get that answer;
> what I get is the same integral written in a slightly different form.
>
> Can someone reproduce that behaviour? And, if it is possible to
> reproduce it, can someone *explain* it?
>
> BTW, the value (1/3)*(4 - Sqrt) is the value of the integral when
> a = 0.
>
> Best regards,
>
> Jose Carlos Santos
>
>
>

```

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