Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2005
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2005

[Date Index] [Thread Index] [Author Index]

Search the Archive

((a&&b)||c)==((a||c)&&(b||c))

  • To: mathgroup at smc.vnet.net
  • Subject: [mg62015] ((a&&b)||c)==((a||c)&&(b||c))
  • From: "Steven T. Hatton" <hattons at globalsymmetry.com>
  • Date: Wed, 9 Nov 2005 03:45:29 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Why does Mathematica not determine that the following is true?

((a \[And] b) \[Or] c) == ((a \[Or] c) \[And] (b \[Or] c))

This little function shows that the lhs  and rhs have the same truth tables,
and are therefore equivalent:

TruthTable[s_, argc_] := Module[
    {tt = Tuples[{True, False}, argc]},
    {#, s @@ #} & /@ tt // TableForm
    ]

-- 
The Mathematica Wiki: http://www.mathematica-users.org/
Math for Comp Sci http://www.ifi.unizh.ch/math/bmwcs/master.html
Math for the WWW: http://www.w3.org/Math/


  • Prev by Date: Re: Mathematica 1
  • Next by Date: Re: Mathematica 1
  • Previous by thread: Re: Write, Put,..
  • Next by thread: Re: ((a&&b)||c)==((a||c)&&(b||c))