Re: ((a&&b)||c)==((a||c)&&(b||c)) is not true
- To: mathgroup at smc.vnet.net
- Subject: [mg62086] Re: ((a&&b)||c)==((a||c)&&(b||c)) is not true
- From: "Steven T. Hatton" <hattons at globalsymmetry.com>
- Date: Fri, 11 Nov 2005 02:51:49 -0500 (EST)
- References: <200511090845.DAA17387@smc.vnet.net> <firstname.lastname@example.org> <email@example.com>
- Sender: owner-wri-mathgroup at wolfram.com
Richard Fateman wrote:
> A good reason for Mathematica to fail to show that these
> are the same, is that they are in some senses different.
> These look like logical statements and as such they look like they
> are logically identical, but these are actually
> programs with short-circuit evaluation.
> c := (Print[C_called]; True)
> a := (Print[A_called]; False)
> b := (Print[B_called]; True)
> (a && b) || c
> (a || c) && (b || c)
> They are different PROGRAMS.
Good observation. There should, however, be some way to tell Mathematica to
treat them as traditional symbolic logic statements. I don't believe that
LogicExpand will do that for me. I'm not sure what happens with Implies,
but my observation is that it does not handle all cases.
The Mathematica Wiki: http://www.mathematica-users.org/
Math for Comp Sci http://www.ifi.unizh.ch/math/bmwcs/master.html
Math for the WWW: http://www.w3.org/Math/
Prev by Date:
Re: Plot Angle between Vectors
Next by Date:
Re: FileNamesin a loop..
Previous by thread:
Next by thread: