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MathGroup Archive 2005

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Re: Re: Recursion

  • To: mathgroup at smc.vnet.net
  • Subject: [mg62326] Re: [mg62315] Re: Recursion
  • From: Bob Hanlon <hanlonr at cox.net>
  • Date: Sun, 20 Nov 2005 04:50:30 -0500 (EST)
  • Reply-to: hanlonr at cox.net
  • Sender: owner-wri-mathgroup at wolfram.com

It blows up because you did not restrict the definition to Integers. It starts 
recursing with the symbolic terms in the definition.  Use

x[t_Integer] = Piecewise[{{2, t ? 0}, {a x[t - 1](1 - x[t - 1]), 5 > t > 0}}];


Bob Hanlon

> 
> From: "Chris Chiasson" <chris.chiasson at gmail.com>
To: mathgroup at smc.vnet.net
> Date: 2005/11/19 Sat PM 11:18:51 EST
> Subject: [mg62326] [mg62315] Re: Recursion
> 
> Fujio Takata,
> 
> Perhaps the following code will work for you:
> 
> x[Condition[t_,t\[LessEqual]0]]=2
> x[Condition[t_,t>0]]=a x[t-1](1-x[t-1])
> Block[{a=2},Plot[x[t],{t,0,9}]]
> 
> 
> On another note, can anyone explain why the following code blows up?
> 
> x[t_]=Piecewise[{{2,t<=0},{a x[t-1](1-x[t-1]),5>t>0}}]
> 
> Regards,
> --
> http://chrischiasson.com/contact/chris_chiasson
> 
> 


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