Re: Recursion

*To*: mathgroup at smc.vnet.net*Subject*: [mg62310] Re: Recursion*From*: Roger Bagula <rlbagulatftn at yahoo.com>*Date*: Sat, 19 Nov 2005 23:18:37 -0500 (EST)*References*: <dln0s1$ga7$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

There is actually a lot available about the logistic map: http://documents.wolfram.com/mathematica/Demos/SoundGallery/LogisticMap.html logistic[n_Integer]:=Module[{f,t,x},f=Compile[{x,t},Evaluate[(3+ ) x (1-x)]];FoldList[f,0.223,Range[n]]] ListPlay[logistic[8000], SampleRate ->2000] JikaiRF at aol.com wrote: > Dear Sirs, > > I would like to obtain trajectories with respect to x, from the following > relationship: > > > > x(t+1)=a x(t)(1-x(t)) > > > > Here, a means a constant with a constraint, 1 < a < 4, t a positive integer > and x a variable. > I know this difference equation cannot be solved by mathematics directly, > because it is not linear. > So, I would like to follow a numerical series in terms of x, and I need to > know how to program Mathematica for this. > > I look forward to your response. > > > > Sincerely, > > Fujio Takata. >