|
[Date Index]
[Thread Index]
[Author Index]
Circle equation problem
- To: mathgroup at smc.vnet.net
- Subject: [mg61525] Circle equation problem
- From: Daniele Lupo <danwolf80_no_spam_ at libero.it>
- Date: Fri, 21 Oct 2005 00:38:10 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Hi to all.
I've this equation:
Abs[p]^2 == Abs[(G - X + I*Y)/(-1 + G*(X + I*Y))]^2
It represent a circle in the complex plane; X and Y are coordinates in the
complex plane (point is X + I Y), while G, p are complex parameters.
I want to write it in this standard form for a circle in the cartesian
plane:
(X - Xcenter)^2 + (Y - YCenter)^2 - ray^2 == 0
In this way, the center in the complex plane is XCenter + I YCenter,
With some effort I think to be able to solve it by hand, but I want to know
if there's a (easy?) way to find center and ray of the circle with
Mathematica. How can I find Xcenter, YCenter and ray from the original
equation?
Thanks for your answers.
Daniele Lupo
PS: Thank you for all your replies in my previous posts!!! :-)
Prev by Date:
Warning from Piecewise
Next by Date:
Re: (a/b)^2 when a/b is replaced by e won't yield e^2
Previous by thread:
Re: Warning from Piecewise
Next by thread:
Re: Circle equation problem
|