Re: operators for relations in sets

*To*: mathgroup at smc.vnet.net*Subject*: [mg60407] Re: operators for relations in sets*From*: Paul Abbott <paul at physics.uwa.edu.au>*Date*: Thu, 15 Sep 2005 05:16:28 -0400 (EDT)*Organization*: The University of Western Australia*References*: <200509131007.GAA09833@smc.vnet.net> <dg8kar$qiq$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

In article <dg8kar$qiq$1 at smc.vnet.net>, Andrzej Kozlowski <akoz at mimuw.edu.pl> wrote: > First of all, \[SubsetEqual] is not defined in Mathematica. You can > define your own function SubsetEqual as: > > SubsetEqual[A_List, B_List] := Intersection[A, B] == A > > so that > > SubsetEqual[{1},{1,2}] > > True > > etc. If you really want with the help of the Notation package you can > make the infix form A\[SubsetEqual]B equivalent to Subsetequal[A,B] > (although i would not bother). Actually, there is no need to use the Notation package. The infix form {A}\[SubsetEqual]{B} _is_ interpreted automatically as SubsetEqual[A,B]. Cheers, Paul _______________________________________________________________________ Paul Abbott Phone: 61 8 6488 2734 School of Physics, M013 Fax: +61 8 6488 1014 The University of Western Australia (CRICOS Provider No 00126G) AUSTRALIA http://physics.uwa.edu.au/~paul

**Follow-Ups**:**Re: Re: operators for relations in sets***From:*Andrzej Kozlowski <andrzej@yhc.att.ne.jp>

**References**:**operators for relations in sets***From:*"hawkmoon269" <rson@new.rr.com>