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MathGroup Archive 2005

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Re: operators for relations in sets

  • To: mathgroup at
  • Subject: [mg60407] Re: operators for relations in sets
  • From: Paul Abbott <paul at>
  • Date: Thu, 15 Sep 2005 05:16:28 -0400 (EDT)
  • Organization: The University of Western Australia
  • References: <> <dg8kar$qiq$>
  • Sender: owner-wri-mathgroup at

In article <dg8kar$qiq$1 at>,
 Andrzej Kozlowski <akoz at> wrote:

> First of all, \[SubsetEqual] is not defined in Mathematica. You can  
> define your own function SubsetEqual as:
> SubsetEqual[A_List, B_List] := Intersection[A, B] == A
> so that
> SubsetEqual[{1},{1,2}]
> True
> etc. If you really want with the help of the Notation package you can  
> make the infix form A\[SubsetEqual]B equivalent to Subsetequal[A,B]  
> (although i would not bother).

Actually, there is no need to use the Notation package. The infix form 
{A}\[SubsetEqual]{B} _is_ interpreted automatically as SubsetEqual[A,B].


Paul Abbott                                      Phone:  61 8 6488 2734
School of Physics, M013                            Fax: +61 8 6488 1014
The University of Western Australia         (CRICOS Provider No 00126G)    

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