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Re: Bug in Reduce?


In version 5.2 it returns
(a == 0 && b == 0) || (c == 0 && d == 0)
yehuda

On 9/15/05, Kennedy <jack at realmode.com> wrote:
>
> The source of this apparent bug could be my misunderstanding of the
> middle,
> "vars" parameter of Reduce, but it sure seems like the following output
> indicates that c must be 0 for my two equations to be satisfied, when in
> fact if a and b are both 0, c does not need to be 0.
>
> Regards,
> Jack
>
> In[1]:=
> Reduce[{a c - b d == 0, a d + b c == 0}, {a, b, c, d}, Reals] //
> FullSimplify
>
> Out[1]=
> c == 0 && (d == 0 || (a == 0 && b == 0))
>
> (version 5.1 for Windows)
>
>



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