Re: Bug in Reduce?
- To: mathgroup at smc.vnet.net
- Subject: [mg60432] Re: [mg60406] Bug in Reduce?
- From: Chris Chiasson <chris.chiasson at gmail.com>
- Date: Fri, 16 Sep 2005 03:49:23 -0400 (EDT)
- References: <dfrhi4$g4l$1@smc.vnet.net> <dg8lfv$r8g$1@smc.vnet.net> <200509140926.FAA01590@smc.vnet.net> <200509150916.FAA15875@smc.vnet.net>
- Reply-to: chris.chiasson at gmail.com
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On Mathematica 5.2 on Windows, this calculation returns:
(a == 0 && b == 0) || (c == 0 && d == 0)
On 9/15/05, Kennedy <jack at realmode.com> wrote:
> The source of this apparent bug could be my misunderstanding of the middle,
> "vars" parameter of Reduce, but it sure seems like the following output
> indicates that c must be 0 for my two equations to be satisfied, when in
> fact if a and b are both 0, c does not need to be 0.
>
> Regards,
> Jack
>
> In[1]:=
> Reduce[{a c - b d == 0, a d + b c == 0}, {a, b, c, d}, Reals] //
> FullSimplify
>
> Out[1]=
> c == 0 && (d == 0 || (a == 0 && b == 0))
>
> (version 5.1 for Windows)
>
>
--
Chris Chiasson
http://chrischiasson.com/
1 (810) 265-3161
- References:
- Re: Simplify and Noncommutativity
- From: Robert Schoefbeck <schoefbeck@hep.itp.tuwien.ac.at>
- Bug in Reduce?
- From: "Kennedy" <jack@realmode.com>
- Re: Simplify and Noncommutativity