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Re: Bug in Reduce?


On Mathematica 5.2 on Windows, this calculation returns:
(a == 0 && b == 0) || (c == 0 && d == 0)

On 9/15/05, Kennedy <jack at realmode.com> wrote:
> The source of this apparent bug could be my misunderstanding of the middle,
> "vars" parameter of Reduce, but it sure seems like the following output
> indicates that  c  must be  0  for my two equations to be satisfied, when in
> fact if  a  and  b  are both  0,  c  does not need to be  0.
> 
> Regards,
> Jack
> 
> In[1]:=
> Reduce[{a c - b d == 0, a d + b c == 0}, {a, b, c, d}, Reals] //
> FullSimplify
> 
> Out[1]=
> c == 0 && (d == 0 || (a == 0 && b == 0))
> 
> (version 5.1 for Windows)
> 
> 


-- 
Chris Chiasson
http://chrischiasson.com/
1 (810) 265-3161


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