Integration problem
- To: mathgroup at smc.vnet.net
- Subject: [mg60467] Integration problem
- From: Heidi.Foerster at physics.unige.ch
- Date: Sat, 17 Sep 2005 02:31:48 -0400 (EDT)
- References: <200509160936.FAA05066@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
I have a periodic function
f=1\(2pi) (1-e^{-2a})/(1-2e^{-a}cos(x-x0)+e^{-2a}), and I want to
calculate the first Fourier coefficient, which corresponds to
Integrate[f cos(x),{x,0,2pi}].
The result mathematica tells me is -Cos[x0] Sinh[a].
(The correct result would be Cos[x0] e^{-a}.)
If I set x0 to zero, I get the correct result e^{-a}:
Simplify[Integrate[(f /. x0 -> 0) Cos[x], {x, 0, 2 \[Pi]}], a > 0]
e^{-a}
The problem is, that for x0=0 both outputs don't match.
Can anyone tell me what's wrong?
Heidi
- References:
- Re: solve for a squared variable
- From: Bob Hanlon <hanlonr@cox.net>
- Re: solve for a squared variable