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Re: solve for a squared variable

>ruth.lazkoz at (Ruth Lazkoz) wrote:

>Why does

>Solve[x^2 + y == 1, x^2]

>give and error message? 

Becuase Solve expects a variable as the second argument and you have supplied an expression that is a function of a variable.

>How can I solve for x^2?

x^2/.Solve[x^2 + y == 1, x][[1]]
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