Re: solve for a squared variable

*To*: mathgroup at smc.vnet.net*Subject*: [mg60493] Re: solve for a squared variable*From*: Bill Rowe <readnewsciv at earthlink.net>*Date*: Sun, 18 Sep 2005 01:15:49 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

>ruth.lazkoz at ehu.es (Ruth Lazkoz) wrote: >Why does >Solve[x^2 + y == 1, x^2] >give and error message? Becuase Solve expects a variable as the second argument and you have supplied an expression that is a function of a variable. >How can I solve for x^2? x^2/.Solve[x^2 + y == 1, x][[1]] -- To reply via email subtract one hundred and four