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Re: solve for a squared variable


Ruth,

Manipulate the equation 'by hand'....

x^2 + y == 1
# - y & /@ %
x^2 + y == 1
x^2 == 1 - y

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 


From: Ruth Lazkoz [mailto:ruth.lazkoz at ehu.es]
To: mathgroup at smc.vnet.net


Hi everyone,

Why does 

Solve[x^2 + y == 1, x^2] 

give and error message? How can I solve for x^2?

Thanks,

Ruth 



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