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Re: Problem with limiits

  • To: mathgroup at
  • Subject: [mg65845] Re: Problem with limiits
  • From: Roger Bagula <rlbagulatftn at>
  • Date: Tue, 18 Apr 2006 06:56:40 -0400 (EDT)
  • References: <> <e1vdsq$967$>
  • Sender: owner-wri-mathgroup at

Andrzej Kozlowski wrote:

> For any sequence of real numbers a1,a2, a3 .... converging to a real  
> number L,  any infinite subsequence of it will converge to the same  
> limit L. This is a very basic fact and is in fact true in any  
> complete metric space (a subsequence of a convergent sequence is a  
> Cauchy sequence, and therefore, in a complete metric space, is itself  
> convergent.)
> Given the above,  you only need the fact that there are infinitely  
> many primes (proved by Euclid and before him by Eudoxus).
> Andrzej Kozlowski
What you are saying is that if I have a composite number c[m]
them the Limit:


as well.
What About:
Limit[(1-1/m)^m,m->Infinity] =1/E

Your reasoning gives:
This does give:
Limit[(1 - 1/m^2)^m, m -> Infinity]=1

Thanks for your help.

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