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Re: Using implicit information about row indices


Hi,

build a null square M

L = {{{1, a}, {2, b}}, {{1, c}, {2, d}, {3,
       e}, {4, f}}, {{2, g}, {3, h}, {4, i}}, {{3, k}, {4, l}, {5,  
m}}, {{4,
       n}, {5, p}}};
M = Table[0, {#}, {#}] &@Length@L;

and set the nonzero entries

MapIndexed[(M[[First@#2, First@#1]] = Last@#1) &, L, {2}];M

gives

{{a, b, 0, 0, 0}, {c, d, e, f, 0}, {0, g, h, i, 0}, {0, 0, k, l, m}, {
   0, 0, 0, n, p}}

Adriano Pascoletti


On 31 lug 2006, at 09:45, Diamond, Mark wrote:

> I am wanting to fill a square matrix M (say, r by r)  using  
> information from
> a list, L.
>  The list L is also of length r, but is not a square matrix. It  
> contains
> lists of ordered pairs {col, num}
> It typically looks something like this; I have arranged it into  
> rows so that
> it is more obvious
> {
>   {{1, a}, {2, b}},
>
>   {{1, c}, {2, d}, {3, e}, {4, f}},
>
>  {{2, g}, {3, h}, {4, i}},
>
>  {{3, k}, {4, l}, {5,m}},
>
>  {{4, n}, {5, p}}
>
> }
>
> Now what I am trying to do is, for example, set M[[1,1]]=a, M[[1,2]] 
> =b,
> M[[2,1]]=c, M[[2.2]]=d, M[[2,3]]=e and so forth, and leave (or set)  
> all the
> other entries in M to zero. The row information for M is implicit  
> in the
> structure of the list L; additionally, the column indices as they  
> appear
> within sublist of L are guraranteed to be sequential. It seems with  
> all this
> info, there should be an easy way to fill M correctly, but I have  
> struggled
> without success to do anything other than an iterative process with  
> Do[]. I
> would appreciate any guidance you might have.
>
> Thank you.
>
> Mark Diamond
>
>
>
>


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