Erf[InverseErf] -- making a function and its inverse cancel
- To: mathgroup at smc.vnet.net
- Subject: [mg68998] Erf[InverseErf] -- making a function and its inverse cancel
- From: mktippett at gmail.com
- Date: Sat, 26 Aug 2006 02:04:40 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
How can I get an expression like Erf[InverseErf[0,1/3]] to simplify to
Cos[ArcCos[1/3]] gives 1/3. Is there some assumption that I'm missing?
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Re: benchmark...why don't you send it back?
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this expression doesn't do what I expected - what's wrong?
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